Please check our Instructions to Authors and send your manuscripts to nifs.journal@gmail.com. Next issue: September/October 2024.
Deadline for submissions: 16 November 2024.
User:Galia/test: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 1: | Line 1: | ||
Нека <math>A = \{ \langle x, \mu_{A+1} (x) \rangle | x \in X \}</math> и | Нека <math>A = \{ \langle x, \mu_{A+1} (x) \rangle | x \in X \}</math> и | ||
B = { < x, μ<sub>B</sub>(x) > | x ∈ X } . Тогава | |||
A е подмножество на B, т.е. A се съдържа в B,�когато ( x X )( A(x) ≤ B(x) ) | A е подмножество на B, т.е. A се съдържа в B,�когато ( x X )( A(x) ≤ B(x) ) | ||
Latest revision as of 11:56, 17 March 2012
Нека [math]\displaystyle{ A = \{ \langle x, \mu_{A+1} (x) \rangle | x \in X \} }[/math] и
B = { < x, μB(x) > | x ∈ X } . Тогава
A е подмножество на B, т.е. A се съдържа в B,�когато ( x X )( A(x) ≤ B(x) )